(k+1)^2-(k-1)^2=4k

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Solution for (k+1)^2-(k-1)^2=4k equation: 



(k+1)^2-(k-1)^2=4k

We move all terms to the left:

(k+1)^2-(k-1)^2-(4k)=0

We add all the numbers together, and all the variables

-4k+(k+1)^2-(k-1)^2=0

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